stri_rank: Ranking¶
Description¶
This function ranks each string in a character vector according to a locale-dependent lexicographic order. It is a portable replacement for the base xtfrm
function.
Usage¶
stri_rank(str, ..., opts_collator = NULL)
Arguments¶
|
a character vector |
|
additional settings for |
|
a named list with ICU Collator’s options, see |
Details¶
Missing values result in missing ranks and tied observations receive the same ranks (based on min).
For more information on ICU’s Collator and how to tune it up in stringi, refer to stri_opts_collator
.
Value¶
The result is a vector of ranks corresponding to each string in str
.
References¶
Collation – ICU User Guide, https://unicode-org.github.io/icu/userguide/collation/
See Also¶
The official online manual of stringi at https://stringi.gagolewski.com/
Gagolewski M., stringi: Fast and portable character string processing in R, Journal of Statistical Software 103(2), 2022, 1-59, doi:10.18637/jss.v103.i02
Other locale_sensitive: %s<%()
, about_locale
, about_search_boundaries
, about_search_coll
, stri_compare()
, stri_count_boundaries()
, stri_duplicated()
, stri_enc_detect2()
, stri_extract_all_boundaries()
, stri_locate_all_boundaries()
, stri_opts_collator()
, stri_order()
, stri_sort()
, stri_sort_key()
, stri_split_boundaries()
, stri_trans_tolower()
, stri_unique()
, stri_wrap()
Examples¶
stri_rank(c('hladny', 'chladny'), locale='pl_PL')
## [1] 2 1
stri_rank(c('hladny', 'chladny'), locale='sk_SK')
## [1] 1 2
stri_rank("a" %s+% c(1, 100, 2, 101, 11, 10)) # lexicographic order
## [1] 1 3 6 4 5 2
stri_rank("a" %s+% c(1, 100, 2, 101, 11, 10), numeric=TRUE) # OK
## [1] 1 5 2 6 4 3
stri_rank("a" %s+% c(0.25, 0.5, 1, -1, -2, -3), numeric=TRUE) # incorrect
## [1] 5 4 6 1 2 3
# Ordering a data frame with respect to two criteria:
X <- data.frame(a=c("b", NA, "b", "b", NA, "a", "a", "c"), b=runif(8))
X[order(stri_rank(X$a), X$b), ]
## a b
## 6 a 0.0455565
## 7 a 0.5281055
## 1 b 0.2875775
## 3 b 0.4089769
## 4 b 0.8830174
## 8 c 0.8924190
## 2 <NA> 0.7883051
## 5 <NA> 0.9404673